The bulky object—possibly the core of a failed gas giant—challenges what astronomers think about how planets form.
  • zhunk@beehaw.orgEnglish
    1·
    1 year ago

    For a geostationary orbit, which is where the center of mass of a space elevator would be:

    h = ³√ G * m * T² / ( 4 * π² ) - r

    • h: orbit height (m)
    • G: gravitational constant
    • m: mass of celestial body (kg)
    • T: period of rotation (s)
    • r: radius of celestial body (m)

    So, if the mass goes way up, the height of the orbit will, too, unless something crazy happens like the planet spinning super fast.